document.write( "Question 251458: (6v^2/(5v^2-10v-15))*(5v-15)/2v \n" ); document.write( "
Algebra.Com's Answer #183896 by PRMath(133)\"\" \"About 
You can put this solution on YOUR website!
(6v^2/(5v^2-10v-15))*(5v-15)/2v\r
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\n" ); document.write( "\n" ); document.write( "\"6v%5E2\"/\"5v%5E2-10v-15\" * \"5v-15\"/\"2v\" (original equation)\r
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\n" ); document.write( "\n" ); document.write( "\"6v%5E2%29\"/\"5%28v%5E2+-+2v+-3%29\" * \"5%28v+-+3%29\"/\"2v\" (factored denominator in first equation by dividing 5. Also factored numerator of 2nd equation by dividing 5) \r
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\n" ); document.write( "\n" ); document.write( "\"6v%5E2\"/\"5%28v+-+3%29%28v%2B1%29\" * \"5%28v+-+3%29\"/\"2v\" (factored the denominator of the first equation even further)\r
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\n" ); document.write( "\n" ); document.write( "Now that you have factored everything, you can begin to cancel factors.\r
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\n" ); document.write( "\n" ); document.write( "The \"5%28v+-+3%29\" in the numerator will cancel the \"5%28v+-+3%29\" in the denominator.\r
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\n" ); document.write( "\n" ); document.write( "The \"6v%5E2\" in the numerator and the \"2v\" in the denominator will reduce to: \"3v\".\r
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\n" ); document.write( "\n" ); document.write( "Our final answer is: \"3v\"/\"v+%2B+1\"\r
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\n" ); document.write( "\n" ); document.write( "If you look at my youtube videos at this site, \r
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\n" ); document.write( "\n" ); document.write( "(www.youtube.com/user/PRMathChicago)\r
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\n" ); document.write( "\n" ); document.write( "you will see a few more examples of problems like these, k? :-) The explanations are a little better with words spoken. :-) You'll have to click on \"See all\" to see all the videos, but there are problems just like this at the site).\r
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\n" ); document.write( "\n" ); document.write( "I hope this helps you. :-)
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