document.write( "Question 251578: Can someone help me with these two questions? Thanks\r
\n" ); document.write( "\n" ); document.write( "1. Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Transform the second expression into the equivalent logarithmic equation; and evaluate the logarithmic equation for three values of x that are greater than 1, three values of x that are between 0 and 1, and at x=1. Use the resulting ordered pairs to plot the graph of each function; y=2^x, x=2^y\r
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\n" ); document.write( "\n" ); document.write( "8. Evaluate the exponential function for three positive values of x, three negative values of x, and at x=0. Show your work. Use the resulting ordered pairs to plot the graph; State the domain and the range of the function.\r
\n" ); document.write( "\n" ); document.write( "f(x) = e^-x -1
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Algebra.Com's Answer #183892 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
first equatioon is y = 2^x\r
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\n" ); document.write( "\n" ); document.write( "values of x are:\r
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\n" ); document.write( "\n" ); document.write( "-3
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\n" ); document.write( "1
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\n" ); document.write( "\n" ); document.write( "when x = -3, 2^x = 2^(-3) = 1/2^3 = 1/8\r
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\n" ); document.write( "\n" ); document.write( "when x = -2, 2^x = 2^(-2) = 1/2^2 = 1/4\r
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\n" ); document.write( "\n" ); document.write( "when x = -1, 2^x = 2^(-1) = 1/2^1 = 1/2\r
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\n" ); document.write( "\n" ); document.write( "when x = 0, 2^x = 2^0 = 1\r
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\n" ); document.write( "\n" ); document.write( "when x = 1, 2^x = 2^1 = 2\r
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\n" ); document.write( "\n" ); document.write( "when x = 2, 2^x = 2^2 = 4\r
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\n" ); document.write( "\n" ); document.write( "when x = 3, 2^x = 2^3 = 8\r
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\n" ); document.write( "\n" ); document.write( "graph of the equation looks like this:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-5%2C5%2C-1%2C10%2C2%5Ex%29\"\r
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\n" ); document.write( "\n" ); document.write( "x = 2^y if and only if \"log%282%2Cx%29+=+y\"\r
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\n" ); document.write( "\n" ); document.write( "this is the same as \"y+=+log%282%2Cx%29\"\r
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\n" ); document.write( "\n" ); document.write( "values for x are:\r
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\n" ); document.write( "\n" ); document.write( ".1
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\n" ); document.write( ".7
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\n" ); document.write( "\n" ); document.write( "when x = .1, y = \"log%282%2Cx%29\" = \"log%282%2C.1%29\" = \"log%2810%2C.1%29%2Flog%2810%2C2%29+=+-3.321928095\"\r
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\n" ); document.write( "\n" ); document.write( "when x = .4, y = \"log%282%2Cx%29\" = \"log%282%2C.4%29\" = \"log%2810%2C.4%29%2Flog%2810%2C2%29+=+-1.321928095\"\r
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\n" ); document.write( "\n" ); document.write( "when x = .7, y = \"log%282%2Cx%29\" = \"log%282%2C.7%29\" = \"log%2810%2C.7%29%2Flog%2810%2C2%29+=+-.0514573173\"\r
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\n" ); document.write( "\n" ); document.write( "when x = 1, y = \"log%282%2Cx%29\" = \"log%282%2C1%29\" = \"log%2810%2C1%29%2Flog%2810%2C2%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "when x = 2, y = \"log%282%2Cx%29\" = \"log%282%2C2%29\" = \"log%2810%2C2%29%2Flog%2810%2C2%29+=+1\"\r
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\n" ); document.write( "\n" ); document.write( "when x = 3, y = \"log%282%2Cx%29\" = \"log%282%2C3%29\" = \"log%2810%2C3%29%2Flog%2810%2C2%29+=+1.584962501\"\r
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\n" ); document.write( "\n" ); document.write( "when x = 4, y = \"log%282%2Cx%29\" = \"log%282%2C4%29\" = \"log%2810%2C4%29%2Flog%2810%2C2%29+=+2\"\r
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\n" ); document.write( "\n" ); document.write( "graph of this equation looks like this:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-1%2C5%2C-1%2C5%2Clog%282%2Cx%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "graph of both equations together looks like this:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-5%2C10%2C-5%2C10%2C2%5Ex%2Clog%282%2Cx%29%2Cx%29\"\r
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\n" ); document.write( "\n" ); document.write( "since the equation of y = 2^x is the inverse of equation x = 2^y, these equations are symmetric about the line y = x as shown in the graph.\r
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\n" ); document.write( "\n" ); document.write( "8. Evaluate the exponential function for three positive values of x, three negative values of x, and at x=0. Show your work. Use the resulting ordered pairs to plot the graph; State the domain and the range of the function.
\n" ); document.write( "f(x) = e^-x -1\r
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\n" ); document.write( "\n" ); document.write( "equation is \"e%5E%28-x%29+-+1\"\r
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\n" ); document.write( "\n" ); document.write( "values of x are:\r
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\n" ); document.write( "\n" ); document.write( "-3,-2,-1,0,1,2,3\r
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\n" ); document.write( "\n" ); document.write( "when x = -3, equation becomes \"e%5E%28-%28-3%29%29+-+1\" = \"e%5E%283%29-1\" = 19.08553692\r
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\n" ); document.write( "\n" ); document.write( "when x = -2, equation becomes \"e%5E%28-%28-2%29%29+-+1\" = \"e%5E%282%29-1\" = 6.389056099\r
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\n" ); document.write( "\n" ); document.write( "when x = -1, equation becomes \"e%5E%28-%28-1%29%29+-+1\" = \"e%5E%281%29-1\" = 1.718281828\r
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\n" ); document.write( "\n" ); document.write( "when x = 0, equation becomes \"e%5E%280%29+-+1\" = 0\r
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\n" ); document.write( "\n" ); document.write( "when x = 1, equation becomes \"e%5E%28-1%29\" = -.632120559\r
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\n" ); document.write( "\n" ); document.write( "when x = 2, equation becomes \"e%5E%28-2%29-1\" = -.864664717\r
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\n" ); document.write( "\n" ); document.write( "when x = 3, equation becomes \"e%5E%28-3%29-1\" = -.950212932\r
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\n" ); document.write( "\n" ); document.write( "graph of equation looks like this:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28600%2C600%2C-5%2C15%2C-3%2C25%2Ce%5E%28-x%29-1%29\"\r
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\n" ); document.write( "\n" ); document.write( "the domain of the equation is all real values of x.\r
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\n" ); document.write( "\n" ); document.write( "the range of the equation is all real values of y > -1\r
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\n" ); document.write( "\n" ); document.write( "x will never be less then or equal to -1.\r
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