document.write( "Question 251610: Given- Isosceles triangle ABC with segment Ab congruent to segment AC
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document.write( "line CD is perpendicular to AB.
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document.write( "Prove- Segment BC multiplied by segment BC is equal to two times segment AB multiplied by segment BD \n" );
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Algebra.Com's Answer #183873 by vksarvepalli(154)![]() ![]() You can put this solution on YOUR website! consider the triangle BCD which is a right angled triangle\r \n" ); document.write( "\n" ); document.write( "now using Pythagoras theorem we get \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now consider the triangle ACD which is also a right angled triangle\r \n" ); document.write( "\n" ); document.write( "again using Pythagoras th. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "but AB=AC (isosceles) \r \n" ); document.write( "\n" ); document.write( "so substituting it in 2 we get \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "but AB=AD+DB\r \n" ); document.write( "\n" ); document.write( "so, \n" ); document.write( "\n" ); document.write( "i.e., \n" ); document.write( "\n" ); document.write( "on simplifying we get \n" ); document.write( "\n" ); document.write( "substituting the value of CD^2 in equation 1\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "taking out BD common in the right hand side of the equation \r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "but AD+BD=AB\r \n" ); document.write( "\n" ); document.write( "therefore |