document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252104>Question 252104</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The two sides of a right triangle differ by one. If the hypotenuse is 29cm, then determine the lenghts of the two sides. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183865 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183865\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two sides be x,x+1<BR>\n" );
document.write( "Then, x^2+(x+1)^2 = (29)^2<BR>\n" );
document.write( "      x^2+x^2+2x+1= 841<BR>\n" );
document.write( "      2x^2+2x-840 = 0<BR>\n" );
document.write( "        x^2+x-420 = 0<BR>\n" );
document.write( "     (x+21)(x-20) = 0 <BR>\n" );
document.write( "               x  = 20 or -21<BR>\n" );
document.write( "Therefore the lengths of the sides are 20 cms , 21 cms and 29cms </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );