document.write( "Question 252022: (2-4i)/(2)
\n" ); document.write( "(2+4i)/(-5+2i)
\n" ); document.write( "(1-i)/(-4-6i)
\n" ); document.write( "(3+5i)/(-2+i)
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Algebra.Com's Answer #183861 by palanisamy(496)\"\" \"About 
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(2-4i)/2 = 2(1-2i)/2 = 1-2i\r
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\n" ); document.write( "\n" ); document.write( "(2+4i)/(-5+2i) = (2+4i)(-5-2i)/(-5+2i)(-5-2i)
\n" ); document.write( " = (-10-4i+20i+8)/[(-5)^2-(2i)^2]
\n" ); document.write( " = (-2+14i)/(25+4)
\n" ); document.write( " = 2(-1+7i)/29\r
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\n" ); document.write( "\n" ); document.write( "(1-i)/(-4-6i) = (1-i)(-4+6i)/(-4-6i)(-4+6i)
\n" ); document.write( " = (-4+6i+4i+6)/[(-4)^2-(6i)^2]
\n" ); document.write( " = (2+10i)/(16+36)
\n" ); document.write( " = 2(1+5i)/52
\n" ); document.write( " = (1+5i)/26\r
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\n" ); document.write( "\n" ); document.write( "(3+2i)/(-2+i) = (3+2i)(-2-i)/(-2+i)(-2-i)
\n" ); document.write( " = (-6-3i-4i+2)/ [(-2)^2-(i)^2]
\n" ); document.write( " = (-4-7i)/(4+1)
\n" ); document.write( " = -(4+7i)/5
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