document.write( "Question 252074: two airplanes start out 10,000 miles apart. one plane heads east and the other heads west traveling at a rate 100 mph faster than the other plane. after how many hours will they pass each other? \n" ); document.write( "
Algebra.Com's Answer #183848 by ankor@dixie-net.com(22740)\"\" \"About 
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two airplanes start out 10,000 miles apart.
\n" ); document.write( " one plane heads east and the other heads west traveling at a rate 100 mph faster than the other plane. after how many hours will they pass each other?
\n" ); document.write( ":
\n" ); document.write( "There are multiple solutions to this problem
\n" ); document.write( "Let s = speed of the slower plane
\n" ); document.write( "then
\n" ); document.write( "(s+100) = speed of the faster speed
\n" ); document.write( ":
\n" ); document.write( "Both planes travel the same length of time (t)
\n" ); document.write( ":
\n" ); document.write( "Write a distance equation Dist = speed * time:
\n" ); document.write( ":
\n" ); document.write( "Slow plane dist = fast plane dist = 10,000 miles
\n" ); document.write( "ts + t(s+100) = 10000
\n" ); document.write( "ts + ts + 100t = 10000
\n" ); document.write( "2ts + 100t = 10000
\n" ); document.write( "t(2s + 100) = 10000
\n" ); document.write( "t = \"10000%2F%282s%2B100%29\" = \"10000%2F%282%28s%2B50%29%29\" = \"5000%2F%28s%2B50%29\"
\n" ); document.write( ":
\n" ); document.write( " t = \"5000%2F%28s%2B50%29\"
\n" ); document.write( ":
\n" ); document.write( "Enter the speed (s) of the slower plane to get the time (t)
\n" ); document.write( "For example
\n" ); document.write( "s = 200 mph; t = 20 hrs
\n" ); document.write( "s = 1200 mph; t = 4 hrs
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