document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252089>Question 252089</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can I please get help on this word problem? The sum of two numbers is 46. Four times one number is 4 more than twice the other number. Find the numbers. So far I have tried many times but always end up with an impossible answer. One thing I have tried is, 4x + 2x + 4 = 6(42). But I always end up getting 41 and 1/3. Can you please teach me how to do this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183842 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183842\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First we have two unknowns and need two equations.<BR>\n" );
document.write( "The first thing we learn is the two numbers add up to 46<BR>\n" );
document.write( "n+m=46<BR>\n" );
document.write( "Now the next part is a bit hard to understand so lets break it down.<BR>\n" );
document.write( "(four times one number)4n <BR>\n" );
document.write( "It doesn't matter at this point which one- n or m will do.<BR>\n" );
document.write( "so I choose n<BR>\n" );
document.write( "then it says that 4n is (means =} 4 more (4+ )than twice the other number 2m\r<BR>\n" );
document.write( "\n" );
document.write( "4n=4+2m<BR>\n" );
document.write( "so now we have our two equations in two unknowns<BR>\n" );
document.write( "n+m=46<BR>\n" );
document.write( "4n=4+2m<BR>\n" );
document.write( "solve the first one for either m or n it doesn't matter<BR>\n" );
document.write( "n=46-m<BR>\n" );
document.write( "or <BR>\n" );
document.write( "m=46-n<BR>\n" );
document.write( "just choose one and stick with it all the way<BR>\n" );
document.write( "4n=4+2m<BR>\n" );
document.write( "every time we see n in the above equation we will put 46-m<BR>\n" );
document.write( "4(46-m)=4+2m<BR>\n" );
document.write( "now we have one equation with one unknown<BR>\n" );
document.write( "so now we just have bring everything together and combine and get the all the m's on one side  and all the numbers on the pother\r<BR>\n" );
document.write( "\n" );
document.write( "first let's multiply out<BR>\n" );
document.write( "4*46-4m=4+2m<BR>\n" );
document.write( "add 4 m to both sides<BR>\n" );
document.write( "4*46=4+6m<BR>\n" );
document.write( "4*45+4*1=4*1+6m<BR>\n" );
document.write( "subtract 4*1 from both sides<BR>\n" );
document.write( "4*45=6m<BR>\n" );
document.write( "(2*2)*(3*15)<BR>\n" );
document.write( "2*3*2*15=6m<BR>\n" );
document.write( "6*30=6m<BR>\n" );
document.write( "divide by 6<BR>\n" );
document.write( "30=m<BR>\n" );
document.write( "46-m=n<BR>\n" );
document.write( "46-30=n<BR>\n" );
document.write( "16=n<BR>\n" );
document.write( "so far so good<BR>\n" );
document.write( "now we go back to the second equation and check our work<BR>\n" );
document.write( "4n=4+2m<BR>\n" );
document.write( "4*16=4+2(30)<BR>\n" );
document.write( "64=64<BR>\n" );
document.write( "ok<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );