document.write( "Question 252088: Given: ABCD is a parallelogram, AB=3x-1, BC=x+23, and CD=2x+11. Show that ABCD is a rhombus. \n" ); document.write( "
Algebra.Com's Answer #183841 by unlockmath(1688)![]() ![]() You can put this solution on YOUR website! Hello, \n" ); document.write( "Let's find the value of x. We can do this by setting up AB=3x-1, CD=2x+11 equal to each other like this: \n" ); document.write( "3x-1=2x+11 Subtract 2x and add 1 to both sides will give us: \n" ); document.write( "x=12 \n" ); document.write( "Now plug 12 into each of the sides and we'll see that each side equals 35 therefore the shape is a Rhombus because the 4th side has to be the same since it's a parallelogram. \n" ); document.write( "RJ \n" ); document.write( "Check out the new math book at \n" ); document.write( "www.math-unlock.com \n" ); document.write( " |