document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252046>Question 252046</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I graph the quadratic functionof y= -x to the 2nd power minus 4x plus 2? And how do I Label the vertex and axis of symmetry? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183831 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> How do I graph the quadratic functionof y= -x to the 2nd power minus 4x plus 2? And how do I Label the vertex and axis of symmetry?<BR>\n" );
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document.write( "y = -x^2-4x+2<BR>\n" );
document.write( "a = -1 ; b = -4 ; c = 2<BR>\n" );
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document.write( "Vertex occurs where x = -b/2a = 4/(2*-1) = -2<BR>\n" );
document.write( "f(-2) = -(-2)^2-4(-2)+2 = 6<BR>\n" );
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document.write( "Plot the vertex at (-2,6)<BR>\n" );
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document.write( "y-intercept = f(0) = 2<BR>\n" );
document.write( "Plot the point (0,2)<BR>\n" );
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document.write( "Since \"a\" is negative the parabola opens downward and has a max at (-2,6)<BR>\n" );
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document.write( "With that information you should be able to sketch the graph.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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