document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=252070>Question 252070</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the width of a rectangle is 3 yards less than its legth. the perimeter is 130 yards. find the length and width of the rectangle show the work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183808 by </B><A HREF=/tutors/aboutme.mpl?userid=MRperkins><B>MRperkins(300)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MRperkins><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MRperkins><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let w represent width and L represent length (you usually use lower-case L but it looks very close to a 1 so I chose to use a capital letter to avoid confusion)  example of 1's and l'sl1l1l1l1<BR>\n" );
document.write( "w=L-3<BR>\n" );
document.write( "the perimeter is the sum of all the sides and can be written as w+w+L+L=130<BR>\n" );
document.write( "combine your like terms<BR>\n" );
document.write( "2w+2L=130  <===official perimeter formula for a rectangle<BR>\n" );
document.write( "Substitute L-3 for w<BR>\n" );
document.write( "2(L-3)+2L=130<BR>\n" );
document.write( "2L-6++2L=130<BR>\n" );
document.write( "4L=136<BR>\n" );
document.write( "L=34<BR>\n" );
document.write( "Since w=L-3, then w=34-3 or w=31<BR>\n" );
document.write( "Length=34, Width=31<BR>\n" );
document.write( ".<BR>\n" );
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document.write( ".<BR>\n" );
document.write( "Respectfully,<BR>\n" );
document.write( "Justin<BR>\n" );
document.write( "justin.sheppard.tech@hotmail.com<BR>\n" );
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document.write( "</TD></TR></TABLE>\n" );