document.write( "Question 31758: John traveled 135 miles in 4 hours fewer than it took David to travel 945 miles. If the speed of John was three times that of David's, what was the speed of each for how long did each travel? \n" ); document.write( "
Algebra.Com's Answer #18379 by atif.muhammad(135)\"\" \"About 
You can put this solution on YOUR website!
Let's look at our data first:
\n" ); document.write( "David:\r
\n" ); document.write( "\n" ); document.write( "His Distance = 945
\n" ); document.write( "His Time = x
\n" ); document.write( "His Speed = z\r
\n" ); document.write( "\n" ); document.write( "His Time = His Distance divided by His Speed
\n" ); document.write( "His Time = \"945%2Fz\"\r
\n" ); document.write( "\n" ); document.write( "John:\r
\n" ); document.write( "\n" ); document.write( "His Distance = 135
\n" ); document.write( "His Time = Four less than David
\n" ); document.write( "His Speed = Three Times that of David\r
\n" ); document.write( "\n" ); document.write( "His Time = His Distance divided by His Speed
\n" ); document.write( "His Time = \"135%2FThree+Times+that+of+David\"
\n" ); document.write( "His Time = \"135%2F3z\"\r
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\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "John's Time was 4 hrs less than David. Therefore:\r
\n" ); document.write( "\n" ); document.write( "\"135%2F3z\"+4 = \"945%2Fz\"\r
\n" ); document.write( "\n" ); document.write( "I'm sure you can solve this equation. I'll let you finish it off!
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