document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251979>Question 251979</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Susan left her home, on foot, at 9:00 am at 1.5 mph. At 10:00 am her friend,<BR>\n" );
document.write( "following the same route, ran at 5.25 mph to meet her. How many minutes, after<BR>\n" );
document.write( "10:00 am, did the two friends meet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183738 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183738\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the two friends meet t minutes after 10.00 AM<BR>\n" );
document.write( "In t minutes both friends have travelled equal distances<BR>\n" );
document.write( "      [(60+t)x1.5]/60 = [tx5.25]/60<BR>\n" );
document.write( "            90+1.5t   = 5.25 t<BR>\n" );
document.write( "               90     = 3.75t<BR>\n" );
document.write( "                    t = 90 / 3.75<BR>\n" );
document.write( "                    t = 24 minutes </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );