document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251989>Question 251989</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1) If n is a real number, then 2n would never be part of which number set?\r<BR>\n" );
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document.write( "A) a real number (B) an irrational number(C) a rational number (D) an imaginary number (E) an integer\r<BR>\n" );
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document.write( "2) If 2n^2 is an even integer, what is true about n + 1?\r<BR>\n" );
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document.write( "(A) It is an even integer.(B) It is an odd integer.(C) It can be an odd or even integer.(D) It is a prime number. (E) It is a perfect square.\r<BR>\n" );
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document.write( "can you give me explanations please<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183737 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183737\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if n is real, that means that it is not imaginary.\r<BR>\n" );
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document.write( "multiply it by 2 and it is still real.\r<BR>\n" );
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document.write( "all the other options are part of the real number set implying that it could be any of them.\r<BR>\n" );
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document.write( "if 2n^2 is an even integer, what can you say about (n+1)?\r<BR>\n" );
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document.write( "2 * n^2 will always be even because it will be always be divisible by 2 since it was multiplied by 2.\r<BR>\n" );
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document.write( "n+1 should therefore be either even or odd, because n could be either even or odd.\r<BR>\n" );
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