document.write( "Question 251298: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.\r
\n" ); document.write( "\n" ); document.write( "A diver jumps from a 48 foot cliff into the ocean below with an initial velocity of 8 ft/sec. The height of the diver from the ocean after t sec is given by h = -16t2 + 8t + 48. When does the diver hit the water?
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Algebra.Com's Answer #183712 by ankor@dixie-net.com(22740)\"\" \"About 
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A diver jumps from a 48 foot cliff into the ocean below with an initial velocity of 8 ft/sec. The height of the diver from the ocean after t sec is given by h = -16t2 + 8t + 48. When does the diver hit the water?
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\n" ); document.write( "h = the height at t seconds
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\n" ); document.write( "When it hits the water h = 0, therefore:
\n" ); document.write( "-16t^2 + 8t + 48 = 0
\n" ); document.write( "Simplify and change the signs, divide by -8
\n" ); document.write( "2t^2 - t - 6 = 0
\n" ); document.write( "Factor
\n" ); document.write( "(2t + 3)(t - 2) =
\n" ); document.write( "the positive solution
\n" ); document.write( "t = 2 sec
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\n" ); document.write( "Check solution in original equation
\n" ); document.write( "h = -16(2^2) + 8(2) + 48
\n" ); document.write( "h = -16(4) + 16 + 48
\n" ); document.write( "h = -64 + 64
\n" ); document.write( "h = 0 when it hits the water
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\n" ); document.write( "Swimmer will hit the water in 2 seconds from a height of 48 ft
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