document.write( "Question 31778This question is from textbook
\n" ); document.write( ": Please help me with this interest problem! I'm desperate and thankyou upfront
\n" ); document.write( "A realtor borrowed $90,000to develop some property. He was able to borrow part of the money at 11.5% interest and the rest at 12%. The annual interest on the two loans amounts to $10,525. How much was borrowed at each rate?
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Algebra.Com's Answer #18371 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
Let amount invested at 11.5% be \"x\".
\n" ); document.write( "Then amount invested at 12% must be \"90000-x\"
\n" ); document.write( "Interest on 11.5% investment is 11.5%(x)=0.115x
\n" ); document.write( "Interest on 12% investment is 12%(90000-x)=10800-0.12x
\n" ); document.write( "EQUATION:
\n" ); document.write( " Interest + Interest = $10525
\n" ); document.write( "0.115x+10800-0.12x=10525
\n" ); document.write( "Mutiply by 1000 to get rid of the decimals:
\n" ); document.write( "115x + 10800000=120x=10525000
\n" ); document.write( "-5x=-275000
\n" ); document.write( "x=$55,000 (amount invested at 11.5%)
\n" ); document.write( "90,000-55,000= $35,000 (amount invested at 12%)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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