document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251966>Question 251966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have to find the LCD for the given rational expression and convert each rational expression into an equivalent rational expression with the LCD as the denominator.\r<BR>\n" );
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document.write( "4b/75a  and  6/105ab\r<BR>\n" );
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document.write( "I know that 5 and 15 go into each of the denominators but I cannot seem to get the common denominator if I multiply each denominator by 5 or 15.\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183707 by </B><A HREF=/tutors/aboutme.mpl?userid=richwmiller><B>richwmiller(17219)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richwmiller><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richwmiller><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183707\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A common denominator could be 7875=75*105<BR>\n" );
document.write( "but you rightly pointed out that 15 will go into both 75 and 105<BR>\n" );
document.write( "so we divide 7875 by 15 and get 525<BR>\n" );
document.write( "so let's why that works\r<BR>\n" );
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document.write( "Actually we come up with 525<BR>\n" );
document.write( "so to get 525 we multiplied  75*7<BR>\n" );
document.write( "and 105* 5<BR>\n" );
document.write( "so now we have 4b*7/525a<BR>\n" );
document.write( "6*5=30<BR>\n" );
document.write( "30/525ab<BR>\n" );
document.write( "so we have two fractions <BR>\n" );
document.write( "28b/525a and 30/105ab<BR>\n" );
document.write( "the denominators are quite the same yet.<BR>\n" );
document.write( "We still have to multiply 28b/525a by b/b<BR>\n" );
document.write( "28b^2/525ab and 30/525ab\r<BR>\n" );
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document.write( "So from the beginning we could have  found that<BR>\n" );
document.write( "105=15*7 and 75=15*5<BR>\n" );
document.write( "so they share 15 and need to share 5 and 7<BR>\n" );
document.write( "so if we multiply 6/105ab by 5/5 and 4b/75a by 7b/7b<BR>\n" );
document.write( "We will have a LCD of 525ab<BR>\n" );
document.write( "28b^2/525ab and 30/525ab\r<BR>\n" );
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document.write( "Note:<BR>\n" );
document.write( "6/105ab was not in its simplest form<BR>\n" );
document.write( "Multiply by 1/3 over 1/3 gets us 2/35ab </SPAN>\n" );
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