document.write( "Question 250062: At 9:00 A.M., your friends begin hiking at 2 mi/h. You begin from the same place at 9:25 A.M. You hike at 3 mi/h.\r
\n" );
document.write( "\n" );
document.write( "a. How long will you hsve hiked when you catch up with your friends?
\n" );
document.write( "b. At what time will you catch up with your friends? \n" );
document.write( "
Algebra.Com's Answer #183693 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! At 9:00 A.M., your friends begin hiking at 2 mi/h. You begin from the same place at 9:25 A.M. You hike at 3 mi/h. \n" ); document.write( "a. How long will you hsve hiked when you catch up with your friends? \n" ); document.write( "In 25 mins, they've gone 2 mi/hr * (25/60) hr = 5/6 miles \n" ); document.write( "You gain on them at 1 mph (3 - 2) so it'll take you 5/6 hours to catch them, or 50 minutes. \n" ); document.write( "5/6 hours * 3 mph = 5/2 miles = 2.5 miles \n" ); document.write( "--------------------------------------- \n" ); document.write( "b. At what time will you catch up with your friends? \n" ); document.write( "0925 + 50 mins = 1015\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |