document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251926>Question 251926</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the speed of a stream is 5mph. if a boat travles 40 miles downstream in the same time it takes to travel 20 miles upstream, what is the speed of the boat in still water? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183636 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183636\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> D=RT<BR>\n" );
document.write( "40=(R+5)T OR T=40/(R+5)<BR>\n" );
document.write( "20=(R-5)T OR T=20/(R-5)<BR>\n" );
document.write( "BECAUSE THE TIMES ARE THE SAME SET THESE TWO EQUATION EQUAL.<BR>\n" );
document.write( "40/(R+5)=20/(R-5)<BR>\n" );
document.write( "CROSS MULTIPLY<BR>\n" );
document.write( "40(R-5)=20(R+5)<BR>\n" );
document.write( "40R-200=20R+100<BR>\n" );
document.write( "40R-20R=100+200<BR>\n" );
document.write( "20R=300<BR>\n" );
document.write( "R=300/20<BR>\n" );
document.write( "R=15 MPH FOR THE SPEED OF THE BOAT IN STILL WATER.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "40/(15+5)=20/(15-5)<BR>\n" );
document.write( "40/20=20/10<BR>\n" );
document.write( "2=2\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );