document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251846>Question 251846</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A father in his will left all his money to his children in the following manner<BR>\n" );
document.write( "$1000 to the first born and 1/10 of what then remains, then $2000 to the second born and 1/10 of what then remains then $3000 to the third born and 1/10 of what then remains, and so on. When this was done each child had the same amount<BR>\n" );
document.write( "How many children were there?\r<BR>\n" );
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document.write( "a) 6 b) 7 c) 8 d) 9 e) none of these </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183616 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183616\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> $1000 to the first born and 1/10 of what then remains,<BR>\n" );
document.write( " then $2000 to the second born and 1/10 of what then remains<BR>\n" );
document.write( " then $3000 to the third born and 1/10 of what then remains,<BR>\n" );
document.write( " and so on. When this was done each child had the same amount<BR>\n" );
document.write( "How many children were there? <BR>\n" );
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document.write( "let a = original amt to be divided among his children:<BR>\n" );
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document.write( "1sh. 1000 + .1(a-1000) = (1000 + .1a - 100)<BR>\n" );
document.write( "(.1a + 900) = 1st child amt<BR>\n" );
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document.write( "Subtract that from original amt:<BR>\n" );
document.write( "a - (900+.1a) = (.9a - 900)<BR>\n" );
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document.write( "2sh. 2000 + .1[(.9a-900)-2000] = 2000 + .1(.9a-2900) = (2000 + .09a - 290)<BR>\n" );
document.write( "(.09a + 1710) = 2nd child amt<BR>\n" );
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document.write( "It says the shares are equal, therefore we can find a:<BR>\n" );
document.write( "1st child sh = 2nd child sh<BR>\n" );
document.write( ".1a + 900 = .09a + 1710<BR>\n" );
document.write( ".1a - .09a = 1710 - 900<BR>\n" );
document.write( ".01a = 810<BR>\n" );
document.write( "a = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=810%2F.01 ALIGN=MIDDLE  ALT=\"810%2F.01\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "a = $81,000; original amt to be divided<BR>\n" );
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document.write( "Find the share given to the 1st child using the equation<BR>\n" );
document.write( "1sh = .1a + 900<BR>\n" );
document.write( "1sh = .1(81000) + 900<BR>\n" );
document.write( "1sh = 8100 + 900<BR>\n" );
document.write( "1sh = $9000 amt to 1st child<BR>\n" );
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document.write( "Check to see if the 2nd child equation yields the same amt<BR>\n" );
document.write( "2sh = .09a + 1710<BR>\n" );
document.write( "2sh = .09(81000) + 1710<BR>\n" );
document.write( "2sh = 7290 + 1710 <BR>\n" );
document.write( "2sh = $9000 amt to 2nd child, so we are on the right track<BR>\n" );
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document.write( "It asks how many children are there<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=81000%2F9000 ALIGN=MIDDLE  ALT=\"81000%2F9000\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 9 children each getting 9000 </SPAN>\n" );
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