document.write( "Question 251878: I need help understanding the method for solving quadratic equations from India.
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document.write( " The equation is x^2-2x-13=0. I have tried x^2-2x=13
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document.write( " 4x^2-8x=52
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document.write( " 4x^2-8x+4=52+4
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document.write( " 4x^2-8x+4=56
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document.write( "then it asks to take the square root of both sides. Since I cant calculate the square root of 56 I have to believe that I have an error somewhere. Does the negative 2x change my equation?
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document.write( "Thanks for your help. \n" );
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Algebra.Com's Answer #183576 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! Yes the negative 2x changes your equation but it doesn't make it any easier or nicer to solve. \n" ); document.write( "You can't factor this one. \n" ); document.write( "You either need to complete the square or use the quadratic formula \n" ); document.write( "I'll show you complete the square. \n" ); document.write( "And I'll send along the quadratic formula method \n" ); document.write( "Let's start with \n" ); document.write( "x^2-2x=13 \n" ); document.write( "so we take the 1/2 of the 2 =1 and square it which still equals 1 \n" ); document.write( "add 1 to both sides \n" ); document.write( "x^2-2x+1=14\r \n" ); document.write( "\n" ); document.write( "factor (x-1)^2=14 \n" ); document.write( "|x-1|=sqrt(14) \n" ); document.write( "x=1+\-sqrt(14) \n" ); document.write( "----x=1-sqrt(14)= -2.74166--- \n" ); document.write( "---x=1+sqrt(14)= 4.74166--- \n" ); document.write( "where sqrt(14)=3.74166\r \n" ); document.write( "\n" ); document.write( "
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