document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251878>Question 251878</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help understanding the method for solving quadratic equations from India.<BR>\n" );
document.write( " The equation is x^2-2x-13=0. I have tried  x^2-2x=13<BR>\n" );
document.write( "                                            4x^2-8x=52<BR>\n" );
document.write( "                                            4x^2-8x+4=52+4<BR>\n" );
document.write( "                                            4x^2-8x+4=56<BR>\n" );
document.write( "then it asks to take the square root of both sides. Since I cant calculate the square root of 56 I have to believe that I have an error somewhere. Does the negative 2x change my equation?<BR>\n" );
document.write( "Thanks for your help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183575 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183575\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Are you trying to solve x^2 -2x - 13 = 0 for x?\r<BR>\n" );
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document.write( "You will need to use the quadratic formula for easy factoring?\r<BR>\n" );
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document.write( "Understand? </SPAN>\n" );
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