document.write( "Question 251845: A motor car manufacturer makes M cars per week. The production is increased
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Algebra.Com's Answer #183543 by Theo(13342) $\"\"$ $\"About$

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n = n% / 100%.\r
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\n" ); document.write( "\n" ); document.write( "production will be (1+n)*m cars per week.\r
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\n" ); document.write( "\n" ); document.write( "example:\r
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\n" ); document.write( "\n" ); document.write( "let m = 100\r
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\n" ); document.write( "\n" ); document.write( "let n% = 20%\r
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\n" ); document.write( "\n" ); document.write( "n = 20%/100% = .2\r
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\n" ); document.write( "\n" ); document.write( "1+n = 1+.2 = 1.2\r
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\n" ); document.write( "\n" ); document.write( "production will be (1+n)*m = 1.2*100 = 120 cars per week.\r
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\n" ); document.write( "\n" ); document.write( "production has been increased by 20%.\r
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\n" ); document.write( "\n" ); document.write( "(120-100)/100 = 20/100 = .2 * 100% = 20%\r
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