document.write( "Question 251828: Can somebody help me find x: \"%28%281%2F2%29x%29%5E2%2B%28x%29%5E2=sqrt%285%29%5E2\" \n" ); document.write( "
Algebra.Com's Answer #183525 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Take note that \"%28sqrt%285%29%29%5E2=sqrt%285%29%2Asqrt%285%29=sqrt%285%2A5%29=sqrt%2825%29=5\". So \"%28sqrt%285%29%29%5E2=5\". Also, keep in mind that \"%28%281%2F2%29x%29%5E2=%281%2F4%29x%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28%281%2F2%29x%29%5E2%2B%28x%29%5E2=%28sqrt%285%29%29%5E2\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%281%2F4%29x%5E2%2Bx%5E2=5\" Square the individual terms (see above).\r
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\n" ); document.write( "\n" ); document.write( "\"%285%2F4%29x%5E2=5\" Combine like terms (this just amounts to adding fractions).\r
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\n" ); document.write( "\n" ); document.write( "\"5x%5E2=5%2A4\" Multiply both sides by 4.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=%285%2A4%29%2F5\" Divide both sides by 5.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=%28cross%285%29%2A4%29%2Fcross%285%29\" Cancel out the common terms.\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=4\" Simplify.\r
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\n" ); document.write( "\n" ); document.write( "\"x=%22%22%2B-sqrt%284%29\" Take the square root of both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"x=sqrt%284%29\" or \"x=-sqrt%284%29\" Break up the \"plus/minus\" to form two equations.\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" or \"x=-2\" Take the square root of \"4\" to get \"2\".\r
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\n" ); document.write( "\n" ); document.write( "\"x=2\" or \"x=-2\" Combine like terms.\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=2\" or \"x=-2\".
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