document.write( "Question 251829: x^2+2x+9\r
\n" ); document.write( "\n" ); document.write( "I have tried x={-2ħsqrt(2^2-4*1*9)}/2*1
\n" ); document.write( "(quadratic formula: x={-bħsqrt( b^2-4ac)}/2(a))
\n" ); document.write( "Process:
\n" ); document.write( "x={-2ħsqrt(2^2-4*1*9)}/2(1)
\n" ); document.write( "x={-2ħsqrt(4-36)}/2
\n" ); document.write( "x=(-2/2)ħ{sqrt-32/2}
\n" ); document.write( "x=-1ħ(sqrt-32/2)\r
\n" ); document.write( "\n" ); document.write( "Looking for -1ħ2i*sqrt(2), but I can't get there.
\n" ); document.write( "I need the process to find this imaginary root.
\n" ); document.write( "what am I doing wrong?
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Algebra.Com's Answer #183524 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
The trick here lies in simplifying \"sqrt%28-32%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28-32%29\" Start with the given expression \r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28-1%2A32%29\" Factor out a negative 1\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28-1%29%2Asqrt%2832%29\" Break up the square roots using the identity \"sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"i%2Asqrt%2832%29\" Replace \"sqrt%28-1%29\" with \"i\" (remember \"i=sqrt%28-1%29\")\r
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\n" ); document.write( "\n" ); document.write( "Now lets simplify \"sqrt%2832%29\":\r
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\n" ); document.write( "\n" ); document.write( "The goal of simplifying expressions with square roots is to factor the radicand into a product of two numbers. One of these two numbers must be a perfect square. When you take the square root of this perfect square, you will get a rational number.\r
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\n" ); document.write( "\n" ); document.write( "So let's list the factors of 32\r
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\n" ); document.write( "\n" ); document.write( "Factors:\r
\n" ); document.write( "\n" ); document.write( "1, 2, 4, 8, 16, 32\r
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\n" ); document.write( "\n" ); document.write( "Notice how 16 is the largest perfect square, so lets factor 32 into 16*2\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%2816%2A2%29\" Factor 32 into 16*2
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\n" ); document.write( "\"sqrt%2816%29%2Asqrt%282%29\" Break up the square roots using the identity \"sqrt%28x%2Ay%29=sqrt%28x%29%2Asqrt%28y%29\"
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\n" ); document.write( "\"4%2Asqrt%282%29\" Take the square root of the perfect square 16 to get 4
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\n" ); document.write( "This means that the expression \"sqrt%2832%29\" simplifies to \"4%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "So the expression \"sqrt%28-32%29\" simplifies to \"4%2Ai%2Asqrt%282%29\" (just reintroduce \"i\" back in)\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"sqrt%28-32%29=4%2Ai%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "Going back to \"x=%28-2%2B-sqrt%28-32%29%29%2F2\", this expression simplifies to \"x=%28-2%2B-+4i%2Asqrt%282%29%29%2F2\". From there, it reduces to \"x=-1%2B-+2i%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "So the solutions are \"x=-1%2B+2i%2Asqrt%282%29\" or \"x=-1-+2i%2Asqrt%282%29\"
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