document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251817>Question 251817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve quadratic equations using the squaring method. <BR>\n" );
document.write( "x^2+8x-2=0???? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183507 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve quadratic equations using the squaring method. <BR>\n" );
document.write( "x^2+8x-2=0????\r<BR>\n" );
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document.write( "We need a perfect square, like (x+a)^2, on the left side of the equation. To determine what to add to each side to get a perfect square on the left, we look at the coefficient 8 on the x term. Half of 8 is 4. Squaring 4 we get 16 so we need to add 18 to both sides to get 16 on the left:\r<BR>\n" );
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document.write( "x^2 + 8x - 2 + 18 = 18<BR>\n" );
document.write( "x^2 + 8x + 16 = 18<BR>\n" );
document.write( "(x+4)*(x+4) = 18<BR>\n" );
document.write( "(x+4)^2 = 18\r<BR>\n" );
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document.write( "Take the square root of both sides and we have:\r<BR>\n" );
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document.write( "x+4 = sqrt(18)<BR>\n" );
document.write( "x = sqrt(18) - 4<BR>\n" );
document.write( "x = 3*sqrt(2) - 2  </SPAN>\n" );
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