document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251783>Question 251783</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two jets are traveling toward each other and are 4000km apart.  The rate of one jet is 100km/hr faster than the rate of the other.  If the jets pass each other after 2.5 hours, what is the rate of each jet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183468 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Two jets are traveling toward each other and are 4000km apart. The rate of one jet is 100km/hr faster than the rate of the other. If the jets pass each other after 2.5 hours, what is the rate of each jet?<BR>\n" );
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document.write( "closing speed for the two jets is x + x+100 = 2x+100 km/h<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "time = distance/rate = 4000/(2x+100) hrs = 2.5 hrs<BR>\n" );
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document.write( "2000/(x+50) = 2.5<BR>\n" );
document.write( "2.5x + 125 = 2000<BR>\n" );
document.write( "2.5x = 1875<BR>\n" );
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document.write( "x = 750 km/h (speed of the slower jet)<BR>\n" );
document.write( "x+100 = 850 km/h (speed of the faster jet)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. <BR>\n" );
document.write( " </SPAN>\n" );
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