document.write( "Question 251778: log(3) 21 - log(3) 7 = log(3)Y
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Algebra.Com's Answer #183457 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"log%283%2C%2821%29%29-log%283%2C%287%29%29=log%283%2C%28y%29%29\" Start with the given equation.\r
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\n" ); document.write( "\n" ); document.write( "\"log%283%2C%2821%2F7%29%29=log%283%2C%28y%29%29\" Combine the logs on the left side using the identity \"log%28b%2C%28A%29%29-log%28b%2C%28B%29%29=log%28b%2C%28A%2FB%29%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"log%283%2C%283%29%29=log%283%2C%28y%29%29\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "\"3=y\" Since the bases of the logs are equal, the arguments (the expressions inside the logs) are equal.\r
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