document.write( "Question 251765: The perimeter of a rectangle is 26 m. The length is 1 m more than twice the width. Find the dimensions\r
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\n" ); document.write( "P = 2 * L + 2 * W
\n" ); document.write( "A = L * W
\n" ); document.write( "26=
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Algebra.Com's Answer #183439 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Note: we're not asked to find the area, so we don't need the formula A=L*W\r
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\n" ); document.write( "\n" ); document.write( "Since \"The perimeter of a rectangle is 26 m\", we know that \"2L%2B2W=26\". Also, since \"The length is 1 m more than twice the width\", we can say that \"L=2W%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"2L%2B2W=26\" Start with the first equation.\r
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\n" ); document.write( "\n" ); document.write( "\"2%282W%2B1%29%2B2W=26\" Plug in \"L=2W%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"4W%2B2%2B2W=26\" Distribute.\r
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\n" ); document.write( "\n" ); document.write( "\"2%2B6W=26\" Combine like terms on the left side.\r
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\n" ); document.write( "\n" ); document.write( "\"6W=26-2\" Subtract \"2\" from both sides.\r
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\n" ); document.write( "\n" ); document.write( "\"6W=24\" Combine like terms on the right side.\r
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\n" ); document.write( "\n" ); document.write( "\"W=%2824%29%2F%286%29\" Divide both sides by \"6\" to isolate \"W\".\r
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\n" ); document.write( "\n" ); document.write( "\"W=4\" Reduce.\r
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\n" ); document.write( "\n" ); document.write( "So the width is 4 meters.\r
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\n" ); document.write( "\n" ); document.write( "\"L=2W%2B1\" Now go back to the second equation\r
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\n" ); document.write( "\n" ); document.write( "\"L=2%284%29%2B1\" Plug in \"W=4\"\r
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\n" ); document.write( "\n" ); document.write( "\"L=8%2B1\" Multiply\r
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\n" ); document.write( "\n" ); document.write( "\"L=9\" Add\r
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\n" ); document.write( "\n" ); document.write( "So the length is 9 meters.
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