document.write( "Question 251684: Problem: Originally, a rectangle was three times as long as it is wide. When 2 cm were subtracted from the length and 5 cm were added to the width, the resulting rectangle had an area of 90 cm squared. Find the dimensions of the new rectangle.\r
\n" ); document.write( "\n" ); document.write( "hmmmm, I tried this problem...but I keep getting decimal answers when solving :/ We are supposed to use only one variable in the actual equation, and use Quadratic equations to solve. \r
\n" ); document.write( "\n" ); document.write( "My Attempt:\r
\n" ); document.write( "\n" ); document.write( "w=width
\n" ); document.write( "l=length
\n" ); document.write( "l=3w\r
\n" ); document.write( "\n" ); document.write( "Formula-
\n" ); document.write( "A=width(length)
\n" ); document.write( "(3w-2)(w+5)=90
\n" ); document.write( "Then I foiled and got:
\n" ); document.write( "3w^2+13w-100=0
\n" ); document.write( "And I get stuck there :/ I don't think it factors and I'm not sure if I foiled wrong or set it up wrong. :/ Help me, please? Thanks :)\r
\n" ); document.write( "\n" ); document.write( "I put this under Algebra, although I am in Algebra II, I hope that is fine :D
\n" ); document.write( "

Algebra.Com's Answer #183361 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
so far so good
\n" ); document.write( "It factors to
\n" ); document.write( "(w-4)(3w+25) = 0
\n" ); document.write( "which yields two answers 4 and -25/3
\n" ); document.write( "We need a positive answer.
\n" ); document.write( "notice that below that even factored out the 3
\n" ); document.write( "and got 3*(w-4)*(w+8.33)
\n" ); document.write( "so 3w^2+13w-100=3*(w^2+4 1/3 w-33 1/3)which factors into 3*(w-4)*(w+8 1/3)
\n" ); document.write( "You could also have used the quadratic formula. See below
\n" ); document.write( "which would have been the best choice after not finding factors.
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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"3w%5E2%2B13w%2B-100+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%2813%29%5E2-4%2A3%2A-100=1369\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=1369 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-13%2B-sqrt%28+1369+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"w%5B1%5D+=+%28-%2813%29%2Bsqrt%28+1369+%29%29%2F2%5C3+=+4\"
\n" ); document.write( " \"w%5B2%5D+=+%28-%2813%29-sqrt%28+1369+%29%29%2F2%5C3+=+-8.33333333333333\"
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"3w%5E2%2B13w%2B-100\" can be factored:
\n" ); document.write( " \"3w%5E2%2B13w%2B-100+=+3%28w-4%29%2A%28w--8.33333333333333%29\"
\n" ); document.write( " Again, the answer is: 4, -8.33333333333333.\n" ); document.write( "Here's your graph:
\n" ); document.write( "\"graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+3%2Ax%5E2%2B13%2Ax%2B-100+%29\"

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Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation \"aw%5E2%2Bbw%2Bc=0\" (in our case \"1w%5E2%2B4.33333333333333w%2B-33.3333333333333+=+0\") has the following solutons:
\n" ); document.write( "
\n" ); document.write( " \"w%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca\"
\n" ); document.write( "
\n" ); document.write( " For these solutions to exist, the discriminant \"b%5E2-4ac\" should not be a negative number.
\n" ); document.write( "
\n" ); document.write( " First, we need to compute the discriminant \"b%5E2-4ac\": \"b%5E2-4ac=%284.33333333333333%29%5E2-4%2A1%2A-33.3333333333333=152.111111111111\".
\n" ); document.write( "
\n" ); document.write( " Discriminant d=152.111111111111 is greater than zero. That means that there are two solutions: \"+x%5B12%5D+=+%28-4.33333333333333%2B-sqrt%28+152.111111111111+%29%29%2F2%5Ca\".
\n" ); document.write( "
\n" ); document.write( " \"w%5B1%5D+=+%28-%284.33333333333333%29%2Bsqrt%28+152.111111111111+%29%29%2F2%5C1+=+4\"
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( " Quadratic expression \"1w%5E2%2B4.33333333333333w%2B-33.3333333333333\" can be factored:
\n" ); document.write( " \"1w%5E2%2B4.33333333333333w%2B-33.3333333333333+=+1%28w-4%29%2A%28w--8.33333333333333%29\"
\n" ); document.write( " Again, the answer is: 4, -8.33333333333333.\n" ); document.write( "Here's your graph:
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