document.write( "Question 251684: Problem: Originally, a rectangle was three times as long as it is wide. When 2 cm were subtracted from the length and 5 cm were added to the width, the resulting rectangle had an area of 90 cm squared. Find the dimensions of the new rectangle.\r
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document.write( "hmmmm, I tried this problem...but I keep getting decimal answers when solving :/ We are supposed to use only one variable in the actual equation, and use Quadratic equations to solve. \r
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document.write( "My Attempt:\r
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document.write( "w=width
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document.write( "l=length
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document.write( "l=3w\r
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document.write( "Formula-
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document.write( "A=width(length)
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document.write( "(3w-2)(w+5)=90
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document.write( "Then I foiled and got:
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document.write( "3w^2+13w-100=0
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document.write( "And I get stuck there :/ I don't think it factors and I'm not sure if I foiled wrong or set it up wrong. :/ Help me, please? Thanks :)\r
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document.write( "I put this under Algebra, although I am in Algebra II, I hope that is fine :D \n" );
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Algebra.Com's Answer #183361 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! so far so good \n" ); document.write( "It factors to \n" ); document.write( "(w-4)(3w+25) = 0 \n" ); document.write( "which yields two answers 4 and -25/3 \n" ); document.write( "We need a positive answer. \n" ); document.write( "notice that below that even factored out the 3 \n" ); document.write( "and got 3*(w-4)*(w+8.33) \n" ); document.write( "so 3w^2+13w-100=3*(w^2+4 1/3 w-33 1/3)which factors into 3*(w-4)*(w+8 1/3) \n" ); document.write( "You could also have used the quadratic formula. See below \n" ); document.write( "which would have been the best choice after not finding factors. \n" ); document.write( "
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