document.write( "Question 251549: A cubic shipping container had a volume of v3 cubic meters. The height of the container was decreased by a whole number of meters and the width was increased by a whole number of meters so that the volume of the container is now v3 + 2v2 – 3v. Find out the following:\r
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document.write( "a. By how many meters the height was decreased?\r
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document.write( "b. By how many meters the width was increased?
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Algebra.Com's Answer #183339 by Theo(13342)![]() ![]() You can put this solution on YOUR website! v[1] = v^3\r \n" ); document.write( "\n" ); document.write( "v[2] = v^3 + 2v^2 - 3v\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "let a = amount height was decreased. \n" ); document.write( "let b = amount width was increased.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "v * (v-a) * (v+b) = v^3 + 2v^2 - 3v.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "find the roots of v^3 + 2v^2 - 3v.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "set the equation equal to 0 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "v^3 + 2v^2 - 3v = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor out a v to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "v * (v^2 + 2v - 3) = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor v^2 + 2v - 3 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(v-1) * (v+3) * v = 0\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a = 1 \n" ); document.write( "b = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "confirm by substituting in original equation to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "v * (v-1) * (v+3) = (v^2 -v) * (v+3) = v^3 + 3v^2 -v^2 - 3v.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "combine like terms to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "v * (v-1) * (v+3) = v^3 + 2v^2 - 3v\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "since this is identical to the original equation of v^3 + 2v^2 - 3v, then the values for a and b are good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "v*v*v = v^3 = original equation for the cube.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "v*(v-1)*(v+3) = v^3 + 2v^2 - 3v = original equation after taking 1 unit off the length and adding 3 units to the width.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "answer is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "height was decreased by 1 unit. \n" ); document.write( "width was increased by 3 units.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |