document.write( "Question 251592: The length of a rectangle is four inches longer than twice its width. If both dimensions were increased by the length equal to its width, the perimeter would be three inches longer than 3/2 times its original perimeter. Find the dimensions of the original rectangle and its perimeter. \r
\n" ); document.write( "\n" ); document.write( "I tried
\n" ); document.write( "L=4+2w
\n" ); document.write( "LLW+WWL=3+(3/2+P)\r
\n" ); document.write( "\n" ); document.write( "I'm absolutely puzzled. please help me out!!
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Algebra.Com's Answer #183307 by richwmiller(17219)\"\" \"About 
You can put this solution on YOUR website!
\"If both dimensions were increased by the length equal to its width\"
\n" ); document.write( "Maybe it means all dimensions were increased by the original width
\n" ); document.write( "10w+8=3+3/2(6w+8)=new perimeter
\n" ); document.write( "w=7 old width
\n" ); document.write( "L=4+2*7=18 old length
\n" ); document.write( "14+36=50 old perimeter
\n" ); document.write( "new dimensions
\n" ); document.write( "nw=7+7=14
\n" ); document.write( "nl=18+7=25
\n" ); document.write( "28+50=78 new perimeter\r
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