document.write( "Question 251592: The length of a rectangle is four inches longer than twice its width. If both dimensions were increased by the length equal to its width, the perimeter would be three inches longer than 3/2 times its original perimeter. Find the dimensions of the original rectangle and its perimeter. \r
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document.write( "I tried
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document.write( "L=4+2w
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document.write( "LLW+WWL=3+(3/2+P)\r
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document.write( "I'm absolutely puzzled. please help me out!! \n" );
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Algebra.Com's Answer #183307 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! \"If both dimensions were increased by the length equal to its width\" \n" ); document.write( "Maybe it means all dimensions were increased by the original width \n" ); document.write( "10w+8=3+3/2(6w+8)=new perimeter \n" ); document.write( "w=7 old width \n" ); document.write( "L=4+2*7=18 old length \n" ); document.write( "14+36=50 old perimeter \n" ); document.write( "new dimensions \n" ); document.write( "nw=7+7=14 \n" ); document.write( "nl=18+7=25 \n" ); document.write( "28+50=78 new perimeter\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |