document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251618>Question 251618</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A population of 100 grows at a rate of 8% a year forever. What is the size of population at end of year 1? Year 2? Year 3? What is the size of the population at the end of year n (for any integer n)? What algebraic equation would you need to solve to find the number of years x that it would take for our population to reach 200?<BR>\n" );
document.write( "I can figure 1-3 years but I am lost on the rest. Could anyone please help? Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183303 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183303\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Po is starting population __ P is present population\r<BR>\n" );
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document.write( "P = Po (1 + .08)^n\r<BR>\n" );
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document.write( "200 = 100 (1.08)^x\r<BR>\n" );
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document.write( "2 = 1.08^x\r<BR>\n" );
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document.write( "log(2) = x log(1.08)\r<BR>\n" );
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document.write( "log(2) / log(1.08) = x </SPAN>\n" );
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