document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=3999>Question 3999</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Thankx Pieter! \r<BR>\n" );
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document.write( "What are the next two terms of the sequence 32, -48, 72, -108, . . . ?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #1833 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=1833\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  32, -48, 72, -108, . . .<BR>\n" );
document.write( " is a geometric series with common ratio<BR>\n" );
document.write( " r = -48/32 = 72/-48 = -108/ 72 = -3/2\r<BR>\n" );
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document.write( " Let a1 = 32, the general term an of the sequence as<BR>\n" );
document.write( " an = a1 r^(n-1) for n>= 1.\r<BR>\n" );
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document.write( " Hence, the next two terms are a5 = -108 * (-3/2) = 162,(= 32*(-3/2)^4)<BR>\n" );
document.write( " and a6 = 162 * (-3/2) = -243 (= 32*(-3/2)^5)\r<BR>\n" );
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document.write( " Forget another wrong answer.\r<BR>\n" );
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document.write( " Kenny<BR>\n" );
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