document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251595>Question 251595</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An Everglades air boat travels 78 miles downstreat in the same amount of time it requires to move upstream a distance of 48 miles. the boats engines drive in still water at an average rate of 16 mph greater than the rate of the current. find the speed of the boat and the water current. \r<BR>\n" );
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document.write( "i tried <BR>\n" );
document.write( "(16+c)t=48<BR>\n" );
document.write( "(16+c)t=78\r<BR>\n" );
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document.write( "it didnt work. i cant figure this out please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183284 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183284\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> An Everglades air boat travels 78 miles downstreat in the same amount of time it requires to move upstream a distance of 48 miles. the boats engines drive in still water at an average rate of 16 mph greater than the rate of the current. find the speed of the boat and the water current. <BR>\n" );
document.write( "i tried <BR>\n" );
document.write( "(16+c)t=48<BR>\n" );
document.write( "(16+c)t=78 <BR>\n" );
document.write( "it didnt work.<BR>\n" );
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document.write( "Downstream DATA:<BR>\n" );
document.write( "distance = 78 miles ; rate = (c+16+2 = (2c+16) mph ; time = 78/(2c+16) hrs.<BR>\n" );
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document.write( "Upstream DATA:<BR>\n" );
document.write( "distance = 48 miles ; rate = (16+c-c = 16 mph ; time = 48/16 = 3 hrs<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "time down = time up<BR>\n" );
document.write( "78/(2c+16) = 3<BR>\n" );
document.write( "78 = 6c + 48<BR>\n" );
document.write( "6c = 30<BR>\n" );
document.write( "c = 5 mph (speed of the current)<BR>\n" );
document.write( "==================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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