document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251484>Question 251484</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given two similar triangles, the area of the larger triangle is sixteen times the area of the smaller triangle. Find the ratio of the perimeter of the larger triangle to the perimeter of the smaller triangle . </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183176 by </B><A HREF=/tutors/aboutme.mpl?userid=rfadrogane><B>rfadrogane(214)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfadrogane><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rfadrogane><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Since its a similar triangle;<BR>\n" );
document.write( "so, let A1 = the area of the larger triangle<BR>\n" );
document.write( "        A2 = the area of the smaller triangle<BR>\n" );
document.write( "        P1 = the perimeter of the larger triangle<BR>\n" );
document.write( "        P2 = the perimeter of the smaller triangle\r<BR>\n" );
document.write( "\n" );
document.write( "by ratio & proportion:<BR>\n" );
document.write( "    A1 = 16*A2 ----(1)<BR>\n" );
document.write( "   (A1/A2) = (P1/P2)^2 ----(2)<BR>\n" );
document.write( "   substitute (1) into (2)<BR>\n" );
document.write( "   [(16*A2)/A2] = (P1/P2)^2<BR>\n" );
document.write( "taking the sqrt. on both sides;<BR>\n" );
document.write( "   4P2 = P1<BR>\n" );
document.write( "thus, the ratio is:<BR>\n" );
document.write( "   4:1 --- answer<BR>\n" );
document.write( "      </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );