document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251490>Question 251490</A>: <I><SPAN STYLE=\"word-break: break-all;\"> To find the hypotenuse when side a=7, b=3, c= ? . So, a=49, b=9, c=the square root of 58 which is 7.6 according to a calculator, my question is how is the .6 derived solving this by longhand??? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183172 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183172\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> To find the hypotenuse when side a=7, b=3, c= ? . So, a=49, b=9, c=the square root of 58 which is 7.6 according to a calculator, my question is how is the .6 derived solving this by longhand???<BR>\n" );
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document.write( "c = sqrt(49+9)<BR>\n" );
document.write( "c = sqrt(58)<BR>\n" );
document.write( "c = sqrt(2*29)<BR>\n" );
document.write( "c = sqrt(2)*sqrt(29)<BR>\n" );
document.write( "Both of these sqrt's are irrational (endless non-repeating decimals)<BR>\n" );
document.write( "You can approximate the answers in decimal form but you cannot ever<BR>\n" );
document.write( "completely evaluate them in decimal form.<BR>\n" );
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document.write( "sqrt(58) = 7.6158.....endlessly<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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