document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251493>Question 251493</A>: <I><SPAN STYLE=\"word-break: break-all;\"> in the problem -x - y < 3\r<BR>\n" );
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document.write( "how do you get the y to be positive?\r<BR>\n" );
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document.write( "when put in y = mx + b form for graphing linear inequalities </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183163 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183163\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> -x - y < 3<BR>\n" );
document.write( "-y < x+3  now divide all terms by -1.<BR>\n" );
document.write( "y > -x-3 [note: when dividing by a negative value the < sign changes to a > sign].<BR>\n" );
document.write( " <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-x+-3%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+-x+-3%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" > (graph 300x200 pixels, x from -6 to 5, y from -10 to 10, -x -3).  </SPAN>\n" );
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