document.write( "Question 251436: Juice X is 20% real fruit juice while Juice Y is 70% real fruit juice. How many liter of each should be mixed together to make 80 liters that is 50% real juice? \n" ); document.write( "
Algebra.Com's Answer #183113 by stanbon(75887) ![]() You can put this solution on YOUR website! Juice X is 20% real fruit juice while Juice Y is 70% real fruit juice. How many liter of each should be mixed together to make 80 liters that is 50% real juice? \n" ); document.write( "------------------------ \n" ); document.write( "Equation: \n" ); document.write( "real + real = real \n" ); document.write( "0.20x + 0.70(80-x) = 0.50*80 \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "20x + 70*80 - 70x = 50*80 \n" ); document.write( "-50x = -20*80 \n" ); document.write( "x = 160/5 \n" ); document.write( "x = 32 liters (amt. of 20% juice needed in the mixture) \n" ); document.write( "--- \n" ); document.write( "80-x = 48 liters (amt. of 70% juice needed in the mixture) \n" ); document.write( "============================================================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |