document.write( "Question 251414: Solve by the elimination method\r
\n" ); document.write( "\n" ); document.write( "2x + 3 y = 2
\n" ); document.write( "4x + 6y = 4\r
\n" ); document.write( "\n" ); document.write( "The solution is ????? (ordered pair)
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Algebra.Com's Answer #183090 by stanbon(75887)\"\" \"About 
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Solve by the elimination method
\n" ); document.write( "2x + 3 y = 2
\n" ); document.write( "4x + 6y = 4
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\n" ); document.write( "multiply thru the 1st equation by 2:
\n" ); document.write( "4x + 6y = 4
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\n" ); document.write( "Subtract that from the 2nd equation and you get:
\n" ); document.write( "0 = 0
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\n" ); document.write( "That means the 2nd equation is simply a multiple
\n" ); document.write( "of the 1st. The two equations give you the same
\n" ); document.write( "set of points.
\n" ); document.write( "Each point is of the form (x, (-2/3)x + (2/3))
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\n" ); document.write( "The system is said to be dependent because one
\n" ); document.write( "equation is a multiple of the other.
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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