document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=29285>Question 29285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A fishing boat traveled 3 hours against a 6km/hr current.  The return trip took 2 hours.  Find the speed of the boat in still water. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18307 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18307\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> THE FORMULA IS 3(X-6)=2(X+6) OR 3 HOURS AT A THE SPEED OF THE BOAT MINUS THE 6 KM/H CURRENT & THE 2 HOUR RETURN TRIP WAS BOAT PLUS THE 6 KM/H CURRENT <BR>\n" );
document.write( "OR 3X-18=2X+12 OR X=30 KM/HR\r<BR>\n" );
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document.write( "PROOF 3(30-6)=2(30+6) OR 3X24=2X36 OR 72=72    </SPAN>\n" );
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