document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251380>Question 251380</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Juanita has 9 rings in her jewelry box.  Five are gold and 4 are silver.  If she randomly selects 3 rings to wear to a party, find each probabilty.<BR>\n" );
document.write( "I have tried added, multiplied variations and don't exactly understand the process. <BR>\n" );
document.write( "question:  P(exactly 2 silver) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183046 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183046\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> nCr=n!/((n-r)!r!) Combination of n things taken r at a time.<BR>\n" );
document.write( "3 gold: 5C3/9C3=10/84<BR>\n" );
document.write( "2g, 1s: (5C2 * 4C1)/9C3=10*4 / 84 = 40/84<BR>\n" );
document.write( "1g, 2s: (5C1 * 4C2)/9C3= 5*6 /84 = 30/84<BR>\n" );
document.write( "3 silver: 4C3/9C3 = 4/84<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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