document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251371>Question 251371</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Sam can do a job in 4 days that Lisa can do in 6 days and Tom can do in 2 days, how long would the job take if Sam, Lisa and Tom worked together to complete it? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183043 by </B><A HREF=/tutors/aboutme.mpl?userid=JimboP1977><B>JimboP1977(311)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JimboP1977><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JimboP1977><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183043\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> After 1 day Sam has done 1/4 of the job, Lisa 1/6 and Tom 1/2\r<BR>\n" );
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document.write( "x((1/4)+(1/6)+(1/2)) = 1 where x is the number of days for the job to be completed when all three are working.\r<BR>\n" );
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document.write( "x = 1/(((1/4)+(1/6)+(1/2))<BR>\n" );
document.write( "x = 12/11 or in other words it takes 1 and 1/11 of a day to do the job. </SPAN>\n" );
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