document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251322>Question 251322</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of a right triangle which has a perimeter of length 16 meters and a hypotenuse with a length of 7 meters.\r<BR>\n" );
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document.write( "a) sqrt (56)m^2 b) 8m2   c) 10m2   d) 12m2   e) 16m2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #183020 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=183020\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> c=7<BR>\n" );
document.write( "16-7=9=a+b<BR>\n" );
document.write( "b=9-a<BR>\n" );
document.write( "a+(9-a)+7=16<BR>\n" );
document.write( "a^2+b^2=c^2<BR>\n" );
document.write( "a^2+(9-a)^2=c^2<BR>\n" );
document.write( "a^2+81-18a+a^2=49<BR>\n" );
document.write( "2a^2-18a+32=0<BR>\n" );
document.write( "a^2-9a+16=0<BR>\n" );
document.write( "a^2-9a     =-16<BR>\n" );
document.write( "a^2-9a+(81/4)=(81/4)-16 completing the square.<BR>\n" );
document.write( "(x-(9/2))^2=17/4<BR>\n" );
document.write( "x-(9/2)=+-sqrt(17)/2<BR>\n" );
document.write( "x=(9+sqrt17)/2, x=(9-sqrt(17))/2<BR>\n" );
document.write( "((9+sqrt17)/2) * ((9-sqrt(17))/2) * (1/2)<BR>\n" );
document.write( "=8m^2<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Ed </SPAN>\n" );
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