document.write( "Question 31638: 50% of American population is overweight.
\n" ); document.write( "65% of American population develops heart disease
\n" ); document.write( "57% of those overweight get heart disease
\n" ); document.write( "What is the probability of being overweight or having heart disease.
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Algebra.Com's Answer #18300 by mbarugel(146)\"\" \"About 
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Hello!
\n" ); document.write( "The rule we must use here is this:\r
\n" ); document.write( "\n" ); document.write( "Given two events, A and B, then:\r
\n" ); document.write( "\n" ); document.write( "Prob(A or B) = Prob(A) + Prob(B) - Prob(A and B)\r
\n" ); document.write( "\n" ); document.write( "Let's call A to the event that someone is overweight, and B to the event that someone has a heasrt disease. From the problem, we already know:\r
\n" ); document.write( "\n" ); document.write( "Prob(A) = 0.50
\n" ); document.write( "Prob(B) = 0.65\r
\n" ); document.write( "\n" ); document.write( "We now need to find Prob(A and B). For that, we use the last piece of information: 57% of those overweight get heart disease. The overweight percentage is 50% Therefore, 57% of the 50% have a heart disease and are overweight. 57% of 50% is 0.57*0.50 = 0.285. Therefore,\r
\n" ); document.write( "\n" ); document.write( "Prob(A and B) = 0.285\r
\n" ); document.write( "\n" ); document.write( "We conclude that:\r
\n" ); document.write( "\n" ); document.write( "Prob(A or B) = Prob(A) + Prob(B) - Prob(A and B) = 0.50 + 0.65 - 0.285 = 0.865 = 86.5%\r
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\n" ); document.write( "\n" ); document.write( "I hope this helps!\r
\n" ); document.write( "\n" ); document.write( "Get more answers at Online Math Answers.com!
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