document.write( "Question 251228: how to factor: {{16n^4-1}} \n" ); document.write( "
Algebra.Com's Answer #182962 by vksarvepalli(154)\"\" \"About 
You can put this solution on YOUR website!
using this \"%28x%5E2-y%5E2%29=%28x%2By%29%28x-y%29\"\r
\n" ); document.write( "\n" ); document.write( "we get \"%2816n%5E4-1%29=%284n%5E2-1%29%284n%5E2%2B1%29\"\r
\n" ); document.write( "\n" ); document.write( "4n^2-1 can be further divided into (2n+1)(2n-1)\r
\n" ); document.write( "\n" ); document.write( "so \"%2816n%5E4-1%29=%282n-1%29%282n%2B1%29%284n%5E2%2B1%29\" Ans.
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