document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=251182>Question 251182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (a+7)/ 3a^2+14a-49 over a^2+8a+7\r<BR>\n" );
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document.write( "Divide and, if possible, simplify. Show work.\r<BR>\n" );
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document.write( "I don't understand how to do this problem. Could you please help show me how it is done? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #182915 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=182915\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (a+7)/ 3a^2+14a-49 over a^2+8a+7 <BR>\n" );
document.write( "Divide and, if possible, simplify.<BR>\n" );
document.write( "---------------------<BR>\n" );
document.write( "(a+7)/[(3a-7)(a+7)] over [(a+7)(a+1)]<BR>\n" );
document.write( "----<BR>\n" );
document.write( "Cancel(a+7) to get:<BR>\n" );
document.write( "1/[(3a-7)] over [(a+7)(a+1)]<BR>\n" );
document.write( "-----------<BR>\n" );
document.write( "Rewrite:<BR>\n" );
document.write( "[1/(3a-7)]/[(a+7)(a+1)]/1<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Invert the denominator and multiply:<BR>\n" );
document.write( "= 1/[(3a-7)(a+7)(a+1)]<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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