document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=31649>Question 31649</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help please.<BR>\n" );
document.write( "The question reads: The number of bacteria present in a culture after t minutes is given as B=10e^kt. If there are 2167 bacteria present after 15 minutes, kind k.\r<BR>\n" );
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document.write( "(A) 0.384<BR>\n" );
document.write( "(B) 80.678<BR>\n" );
document.write( "(C) 0.359<BR>\n" );
document.write( "(D) 5.379\r<BR>\n" );
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document.write( "Thanks for your help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #18289 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=18289\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Based on the question,<BR>\n" );
document.write( "2167 = 10e^15k<BR>\n" );
document.write( "=> ln(2167) = ln(10) + 15k<BR>\n" );
document.write( "=> 15k = ln(2167) - ln(10) = ln(2167/10) = ln(216.7)<BR>\n" );
document.write( "=> k = (ln216.7)/15<BR>\n" );
document.write( "=> k = .359\r<BR>\n" );
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document.write( "Correct answer: C </SPAN>\n" );
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