document.write( "Question 251057: solve for x:\r
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document.write( "x^3/2(to the 3 over 2) - 27=0
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document.write( "4^x=79
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document.write( "9^x+2=27^x
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document.write( "write the logarithmc equations for the following\r
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document.write( "A = s^2 /4(s to the 2 over 4) sqrt3
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document.write( "R = sqrt3V/mH (R equals the squareroot of 3V over mH)
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Algebra.Com's Answer #182879 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! You have too many questions qrouped together. \n" ); document.write( "Resubmit individually \n" ); document.write( "x^3/2 - 27=0 \n" ); document.write( "x^(2/3)=27 \n" ); document.write( "raise both sides to 2/3 \n" ); document.write( "x^(3/2*2/3)=27^(2/3)\r \n" ); document.write( "\n" ); document.write( "x^1=27^(2/3) \n" ); document.write( "27(2/3)= \n" ); document.write( "27(1/3)=3 \n" ); document.write( "then 3^2=9 \n" ); document.write( " \n" ); document.write( " |