document.write( "Question 251116: Can you please help me with this logarithm equation.. & can you please do it step by step?!?!? I'm gonna try to write this the best I can...\r
\n" ); document.write( "\n" ); document.write( "log cube root of ((9x-8)^2) = 4/3
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Algebra.Com's Answer #182875 by JimboP1977(311)\"\" \"About 
You can put this solution on YOUR website!
Assuming you are using a log of base 10.\r
\n" ); document.write( "\n" ); document.write( "\"log+%28%28%289x-8%29%5E2%29%5E%281%2F3%29%29+=+4%2F3\" \"^(1/3)\" is another way of saying cube root.\r
\n" ); document.write( "\n" ); document.write( "\"%281%2F3%29+%2A+log%28%289x-8%29%5E2%29+=+4%2F3\" using log rule 3
\n" ); document.write( "\"+log+%28%289x-8%29%5E2%29+=+4\" divide both sides by 1/3, (4/3)/(1/3) = (4/3)*(3/1)
\n" ); document.write( "\"+%289x-8%29%5E2+=+10000\" inverse of log base 10 is 10^x,10^4 = 10000
\n" ); document.write( "take the square root of both sides, remember the roots will be negative and positive
\n" ); document.write( "\"+%289x-8%29+=+100\" OR \"%289x-8%29+=+-100\"
\n" ); document.write( "Rearrange to find x
\n" ); document.write( "\"+x+=+12\" OR \"x=+-%2892%2F9%29\"\r
\n" ); document.write( "\n" ); document.write( "Does that make sense?\r
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