document.write( "Question 250999: Can you please help me?!? I have problems with this equation. Can you do it step by step?? I want to see what I'm doing wrong. Please & thank you!\r
\n" ); document.write( "\n" ); document.write( "log (x^2 - 100) = 1 + log (x + 10) \n" ); document.write( "
Algebra.Com's Answer #182834 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
log(x^2 - 100) = 1 + log(x + 10)
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\n" ); document.write( "We can factor the expression on the left (it's the \"difference of squares\")
\n" ); document.write( "log ((x-10)(x+10)) = 1 + log (x + 10)
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\n" ); document.write( "Subtract log(x+10) from both sides
\n" ); document.write( "log ((x-10)(x+10)) - log (x + 10) = 1
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\n" ); document.write( "Can be written as, (subtraction of logs means divide)
\n" ); document.write( "\"log%28%28%28%28x-10%29%28x%2B10%29%29%2F%28x%2B10%29%29%29\" = 1
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\n" ); document.write( "Cancel (x+10) and you have:
\n" ); document.write( "log(x-10) = 1
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\n" ); document.write( "exponent equiv of logs
\n" ); document.write( "10^1 = x - 10
\n" ); document.write( "10 = x - 10
\n" ); document.write( "10 + 10 = x
\n" ); document.write( "x = 20
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\n" ); document.write( "Check this solution on your calc, enter
\n" ); document.write( "log(20^2 - 100) - log(20 + 10) results = 1 \n" ); document.write( "
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